Recipe/Example/Alu Methi
Product
EAN: 8901042957104
Ingredients
Potato (48%), Onion, Tomato, Fenugreek Leaves (12%), Refined Sunflower Oil, Yogurt, Green chilli, Salt, Ginger, Garlic, Coriander Leaves, Cumin and Turmeric Powder
Nutritional values
(4.9, 0.6, 8.1, 1.3, 1.6, 0.94) no fiber
Ciqual
New potato, raw (4023) (0.3, 0.058, 15.9, 0.2, 1.88, 0.058) fiber 1.3
Onion, raw (20034) (0.62, 0.2, 6.25, 4.8, 1.1, 0.098) fiber 1.7
Tomato, raw (20047) (0.26, 0.056, 2.49, 2.48, 0.86, 0.0081) fiber: 1.2
Fenugreek leaves (1, 0, 6, 1, 4, 0)
Sunflower oil (17440) (100, 11.1, 0, 0, 0, .025) no fiber
Yoghurt, plain (average) (19600) (2.3, 1.53, 4.73, 4.67, 3.88, 0.11) fiber: 0.86
Chili pepper, raw (20151) (0.32, 0.031, 7.7, 5.3, 1.87, 0.02) fiber: 1.65
Salt, white (sea, igneous or rock), iodine added, no other enrichment (11058) (0,0,0,0,0,97.8)
Fit Result
NNLS forced order
deviance: 1.22e-05 (perfect fit)

Contribution of onion and tomato forced by oil, contribution of chili forced by salt.
Expected fiber: 0.88
Claude Solver
The solver achieves a perfect fit (residual = 0.002) on all six declared nutrients, estimating S = 84.6 g raw ingredients per 100 g product (yield 118.3%). The yield above 100% reflects water absorption during cooking — typical for a wet curry where cooking liquid is added to create the gravy. Potato (48% declared) accounts for 6.6 g of the 8.1 g carb budget, creating a near-degenerate system for the secondary vegetables: onion, tomato, and fenugreek are nutritionally indistinguishable and all land at the same quantity (10.1 g each).
Yield: 118.3% — the product gains mass from cooking liquid (gravy), consistent with a wet curry.
Two key findings in the analysis:
1. Carbohydrate lock. Potato alone provides 6.58g of the 8.1g carb budget, leaving only 1.52g for 9 other ingredients. This makes onion, tomato, and fenugreek nutritionally indistinguishable — the solver puts them all at exactly the same quantity (12% of S). This is the NNLS plateau: the label cannot tell us whether there's more onion than tomato or vice versa.
2. Oil pins sat_fat precisely. Sunflower oil (11.1% sat_fat) is the only significant fat source, so the 0.6g sat_fat declaration uniquely determines x_oil = 4.6g with no ambiguity.
The initial report
Claude Solver Report, Claude Solver Report version 2
The ingredient recipe indicates some percentages. Is this useful information for the solver? (comparison report).
Transcript of the discussion with Claude on finding the recipe and a better solver.